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annotate lib/CodeGen/LatencyPriorityQueue.cpp @ 120:1172e4bd9c6f

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update 4.0.0
author mir3636
date Fri, 25 Nov 2016 19:14:25 +0900
parents afa8332a0e37
children 3a76565eade5
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1 //===---- LatencyPriorityQueue.cpp - A latency-oriented priority queue ----===//
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2 //
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3 // The LLVM Compiler Infrastructure
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4 //
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5 // This file is distributed under the University of Illinois Open Source
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6 // License. See LICENSE.TXT for details.
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7 //
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8 //===----------------------------------------------------------------------===//
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9 //
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10 // This file implements the LatencyPriorityQueue class, which is a
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11 // SchedulingPriorityQueue that schedules using latency information to
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12 // reduce the length of the critical path through the basic block.
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13 //
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14 //===----------------------------------------------------------------------===//
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15
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16 #include "llvm/CodeGen/LatencyPriorityQueue.h"
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17 #include "llvm/Support/Debug.h"
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18 #include "llvm/Support/raw_ostream.h"
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19 using namespace llvm;
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20
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21 #define DEBUG_TYPE "scheduler"
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22
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23 bool latency_sort::operator()(const SUnit *LHS, const SUnit *RHS) const {
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24 // The isScheduleHigh flag allows nodes with wraparound dependencies that
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25 // cannot easily be modeled as edges with latencies to be scheduled as
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26 // soon as possible in a top-down schedule.
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27 if (LHS->isScheduleHigh && !RHS->isScheduleHigh)
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28 return false;
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29 if (!LHS->isScheduleHigh && RHS->isScheduleHigh)
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30 return true;
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31
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32 unsigned LHSNum = LHS->NodeNum;
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33 unsigned RHSNum = RHS->NodeNum;
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34
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35 // The most important heuristic is scheduling the critical path.
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36 unsigned LHSLatency = PQ->getLatency(LHSNum);
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37 unsigned RHSLatency = PQ->getLatency(RHSNum);
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38 if (LHSLatency < RHSLatency) return true;
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39 if (LHSLatency > RHSLatency) return false;
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40
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41 // After that, if two nodes have identical latencies, look to see if one will
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42 // unblock more other nodes than the other.
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43 unsigned LHSBlocked = PQ->getNumSolelyBlockNodes(LHSNum);
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44 unsigned RHSBlocked = PQ->getNumSolelyBlockNodes(RHSNum);
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45 if (LHSBlocked < RHSBlocked) return true;
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46 if (LHSBlocked > RHSBlocked) return false;
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47
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48 // Finally, just to provide a stable ordering, use the node number as a
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49 // deciding factor.
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50 return RHSNum < LHSNum;
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51 }
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52
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53
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54 /// getSingleUnscheduledPred - If there is exactly one unscheduled predecessor
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55 /// of SU, return it, otherwise return null.
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56 SUnit *LatencyPriorityQueue::getSingleUnscheduledPred(SUnit *SU) {
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57 SUnit *OnlyAvailablePred = nullptr;
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58 for (SUnit::const_pred_iterator I = SU->Preds.begin(), E = SU->Preds.end();
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59 I != E; ++I) {
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60 SUnit &Pred = *I->getSUnit();
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61 if (!Pred.isScheduled) {
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62 // We found an available, but not scheduled, predecessor. If it's the
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63 // only one we have found, keep track of it... otherwise give up.
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64 if (OnlyAvailablePred && OnlyAvailablePred != &Pred)
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65 return nullptr;
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66 OnlyAvailablePred = &Pred;
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67 }
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68 }
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69
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70 return OnlyAvailablePred;
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71 }
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72
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73 void LatencyPriorityQueue::push(SUnit *SU) {
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74 // Look at all of the successors of this node. Count the number of nodes that
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75 // this node is the sole unscheduled node for.
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76 unsigned NumNodesBlocking = 0;
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77 for (SUnit::const_succ_iterator I = SU->Succs.begin(), E = SU->Succs.end();
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78 I != E; ++I) {
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79 if (getSingleUnscheduledPred(I->getSUnit()) == SU)
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80 ++NumNodesBlocking;
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81 }
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82 NumNodesSolelyBlocking[SU->NodeNum] = NumNodesBlocking;
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83
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84 Queue.push_back(SU);
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85 }
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86
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87
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88 // scheduledNode - As nodes are scheduled, we look to see if there are any
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89 // successor nodes that have a single unscheduled predecessor. If so, that
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90 // single predecessor has a higher priority, since scheduling it will make
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91 // the node available.
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92 void LatencyPriorityQueue::scheduledNode(SUnit *SU) {
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93 for (SUnit::const_succ_iterator I = SU->Succs.begin(), E = SU->Succs.end();
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94 I != E; ++I) {
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95 AdjustPriorityOfUnscheduledPreds(I->getSUnit());
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96 }
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97 }
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98
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99 /// AdjustPriorityOfUnscheduledPreds - One of the predecessors of SU was just
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100 /// scheduled. If SU is not itself available, then there is at least one
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101 /// predecessor node that has not been scheduled yet. If SU has exactly ONE
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102 /// unscheduled predecessor, we want to increase its priority: it getting
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103 /// scheduled will make this node available, so it is better than some other
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104 /// node of the same priority that will not make a node available.
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105 void LatencyPriorityQueue::AdjustPriorityOfUnscheduledPreds(SUnit *SU) {
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106 if (SU->isAvailable) return; // All preds scheduled.
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107
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108 SUnit *OnlyAvailablePred = getSingleUnscheduledPred(SU);
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109 if (!OnlyAvailablePred || !OnlyAvailablePred->isAvailable) return;
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110
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111 // Okay, we found a single predecessor that is available, but not scheduled.
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112 // Since it is available, it must be in the priority queue. First remove it.
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113 remove(OnlyAvailablePred);
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114
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115 // Reinsert the node into the priority queue, which recomputes its
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116 // NumNodesSolelyBlocking value.
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117 push(OnlyAvailablePred);
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118 }
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119
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120 SUnit *LatencyPriorityQueue::pop() {
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121 if (empty()) return nullptr;
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122 std::vector<SUnit *>::iterator Best = Queue.begin();
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123 for (std::vector<SUnit *>::iterator I = std::next(Queue.begin()),
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124 E = Queue.end(); I != E; ++I)
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125 if (Picker(*Best, *I))
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126 Best = I;
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127 SUnit *V = *Best;
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128 if (Best != std::prev(Queue.end()))
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129 std::swap(*Best, Queue.back());
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130 Queue.pop_back();
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131 return V;
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132 }
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133
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134 void LatencyPriorityQueue::remove(SUnit *SU) {
95c75e76d11b LLVM 3.4
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135 assert(!Queue.empty() && "Queue is empty!");
120
1172e4bd9c6f update 4.0.0
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136 std::vector<SUnit *>::iterator I = find(Queue, SU);
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137 if (I != std::prev(Queue.end()))
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138 std::swap(*I, Queue.back());
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139 Queue.pop_back();
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140 }