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author Shinji KONO <kono@ie.u-ryukyu.ac.jp>
date Sun, 19 Jun 2022 13:24:53 +0900
parents a5f8084b8368
children 42000f20fdbe
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Constructing ZF Set Theory in Agda 
============

Shinji KONO (kono@ie.u-ryukyu.ac.jp), University of the Ryukyus

## ZF in Agda

```
    zf.agda            axiom of ZF
    zfc.agda           axiom of choice
    Ordinals.agda      axiom of Ordinals
    ordinal.agda       countable model of Ordinals
    OD.agda            model of ZF based on Ordinal Definable Set with assumptions
    ODC.agda           Law of exclude middle from axiom of choice assumptions
    LEMC.agda          model of choice with assumption of the Law of exclude middle 
    OPair.agda         ordered pair on OD

    BAlgbra.agda       Boolean algebra on OD (not yet done)
    filter.agda        Filter on OD (not yet done)
    cardinal.agda      Caedinal number on OD (not yet done)

    logic.agda         some basics on logic
    nat.agda           some basics on Nat
```

## Ordinal Definable Set

It is a predicate has an Ordinal argument.

In Agda, OD is defined as follows.

```
    record OD : Set (suc n ) where
      field
        def : (x : Ordinal  ) → Set n
```

This is not a ZF Set, because it can contain entire Ordinals.

## HOD : Hereditarily Ordinal Definable

What we need is a bounded OD, the containment is limited by an ordinal.

```
    record HOD : Set (suc n) where
      field
        od : OD
        odmax : Ordinal
        <odmax : {y : Ordinal} → def od y → y o< odmax
```

In classical Set Theory, HOD stands for Hereditarily Ordinal Definable, which means

```
     HOD = { x | TC x ⊆ OD }
```

TC x is all transitive closure of x, that is elements of x and following all elements of them are all OD. But 
what is x? In this case, x is an Set which we don't have yet. In our case, HOD is a bounded OD. 

## 1 to 1 mapping between an HOD and an Ordinal

HOD is a predicate on Ordinals and the solution is bounded by some ordinal. If we have a mapping

```
  od→ord : HOD  → Ordinal 
  ord→od : Ordinal  → HOD  
  oiso   :  {x : HOD }      → ord→od ( od→ord x ) ≡ x
  diso   :  {x : Ordinal } → od→ord ( ord→od x ) ≡ x
```

we can check an HOD is an element of the OD using def.

A ∋ x can be define as follows.

```
    _∋_ : ( A x : HOD  ) → Set n
    _∋_  A x  = def (od A) ( od→ord x )

```
In ψ : Ordinal → Set,  if A is a  record { od = { def = λ x → ψ x } ...}  , then

    A ∋ x = def (od A) ( od→ord x ) = ψ (od→ord x)

They say the existing of the mappings can be proved in Classical Set Theory, but we
simply assumes these non constructively.