Mercurial > hg > Members > kono > Proof > automaton
annotate a04/lecture.ind @ 294:248711134141
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author | Shinji KONO <kono@ie.u-ryukyu.ac.jp> |
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date | Wed, 29 Dec 2021 19:08:28 +0900 |
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37 | 1 -title: 非決定性オートマトン |
2 | |
3 決定性オートマトンは入力に対して次の状態が一意に決まる。一つの入力に対して可能な状態が複数ある場合を考える。 | |
141 | 4 例えば、ドアの鍵がテンキーだったら、次に何を入れるかには自由度がある。 |
5 この拡張は容易で、状態遷移関数が状態の代わりに状態のリストを返せば良い。しかし、リストを使うとかなり煩雑になる。 | |
37 | 6 |
141 | 7 このようなものが必要な理由は、 Regular Language の Concatを考えるためである。 |
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8 |
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9 Regular Language は Concatについて閉じている。これは オートマトン A と B があった時に、z を前半 x ++ y |
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10 にわけて x を A が受理し、y を B で受理するものを、単一ののオートマトンで実現できると言う意味である。 |
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11 しかい、 これを決定性オートマトンで示すのは難しい。A ++ B の 境目がどこかを前もって予測することができないからである。 |
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12 |
141 | 13 <center><img src="fig/concat.svg"></center> |
14 | |
15 このためには後半のB automatonを、前半のA automatonが終わる可能性がある時だけ、 | |
16 一文字毎に増やしてやればよい。増やしたものの一つでも成功すればよい。Bが増えるので、その増えた状態を覚えておく必要がある。 | |
17 | |
18 an (Aのn番目の状態)と、b0...bn の部分集合 | |
19 | |
20 状態はAの状態とBの状態の部分集合の組になる。 | |
21 | |
22 --非決定性オートマトン | |
23 | |
24 そこで、状態の部分集合からなるオートマトンを考える。 | |
25 | |
26 これは状態遷移が非決定的な場合に相当する。この場合では 1 が来た時に q1 に | |
27 行っても、q2,q3 に行っても良い。q1から始める。 | |
28 | |
29 q1 0 → q1 | |
30 q1 1 → q1 | |
31 q1 1 → q2 | |
32 q1 1 → q3 | |
33 q2 0 → q3 | |
34 q3 1 → q4 | |
35 q4 0 → q4 | |
36 q4 1 → q4 | |
37 | |
38 最後に q4で accept。 | |
39 | |
40 <center><img src="fig/nfa.svg"></center> | |
41 | |
42 この時に、入力に従って状態の部分集合を計算していく方法でNFAのacceptを決定できる。 | |
43 | |
44 このNFA(nondeterministic automaton)は .*(101|11).* に対応している。 | |
45 | |
46 | |
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47 --Agda での非決定性オートマトン |
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48 |
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49 ここでは、部分集合を写像を使って表す。集合 Q から Bool (true または false) への写像を使う。true になる要素が |
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50 部分集合になる。すると、遷移関数は入力Σと状態から Bool への写像となる。終了条件は変わらない。 |
37 | 51 |
52 record NAutomaton ( Q : Set ) ( Σ : Set ) | |
53 : Set where | |
54 field | |
69 | 55 Nδ : Q → Σ → Q → Bool |
56 Nend : Q → Bool | |
37 | 57 |
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58 これを非決定性オートマトンという。Agda では同じ名前を使いまわしすることはできない(monomorpphism)ので、Nを付けた。 |
37 | 59 |
69 | 60 <a href="../agda/nfa.agda"> nfa.agda </a> |
37 | 61 |
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62 --NAutomatonの受理と遷移 |
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63 |
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64 非決定性オートマトンでは、一つの入力に対して、複数の状態が行き先になる。複数の状態を経由した経路のどれかが |
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65 入力を読み終わった後に、終了状態になれば受理されることになる。 |
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66 |
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67 このためには、状態の集合Qから条件 P : Q → Bool で true になるものを見つけ出す必要がある。 |
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68 |
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69 true になるものは複数あるので、やはり部分集合で表される。つまり、 |
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70 |
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71 exists : ( P : Q → Bool ) → Q → Bool |
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72 |
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73 このような関数を実現する必要がある。 |
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74 |
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75 もし、Q が有限集合なら、P を順々に調べていけばよい。やはり List で良いのだが、ここでは Agda の Data.Fin を使ってみよう。 |
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76 |
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77 --finiteSet |
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78 |
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79 Data.Fin だけを使って記述することもできるが、数字だけというのも味気ない。 |
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80 |
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81 record FiniteSet ( Q : Set ) { n : ℕ } : Set where |
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82 field |
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83 Q←F : Fin n → Q |
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84 F←Q : Q → Fin n |
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85 finiso→ : (q : Q) → Q←F ( F←Q q ) ≡ q |
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86 finiso← : (f : Fin n ) → F←Q ( Q←F f ) ≡ f |
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87 |
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88 という感じで、Data.Fin と 状態を対応させる。そうすると、 |
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89 |
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90 lt0 : (n : ℕ) → n Data.Nat.≤ n |
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91 lt0 zero = z≤n |
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92 lt0 (suc n) = s≤s (lt0 n) |
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93 |
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94 exists1 : (m : ℕ ) → m Data.Nat.≤ n → (Q → Bool) → Bool |
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95 exists1 zero _ _ = false |
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96 exists1 ( suc m ) m<n p = p (Q←F (fromℕ≤ {m} {n} m<n)) \/ exists1 m (lt2 m<n) p |
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97 |
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98 exists : ( Q → Bool ) → Bool |
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99 exists p = exists1 n (lt0 n) p |
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100 |
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101 という形で、 exists を記述することができる。 |
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102 |
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103 <a href="../agda/finiteSet.agda"> finiteSet.agda </a> |
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104 |
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105 |
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106 --NAutomatonの受理と遷移 |
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107 |
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108 状態の受理と遷移は exists を使って以下のようになる。 |
37 | 109 |
110 Nmoves : { Q : Set } { Σ : Set } | |
111 → NAutomaton Q Σ | |
112 → {n : ℕ } → FiniteSet Q {n} | |
104
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113 → ( Qs : Q → Bool ) → (s : Σ ) → Q → Bool |
37 | 114 Nmoves {Q} { Σ} M fin Qs s q = |
104
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115 exists fin ( λ qn → (Qs qn /\ ( Nδ M qn s q ) )) |
37 | 116 |
104
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117 Qs は Q → Bool の型を持っているので、Qs qn は true または false である。今の状態集合 Qs に含まれていて、 |
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118 Nδ M qn s q つまり、非決定オートマトン M の遷移関数 Nδ : Q → Σ → Q → Bool で true を返すものが存在すれば |
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119 遷移可能になる。 |
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120 |
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121 Naccept : { Q : Set } { Σ : Set } |
37 | 122 → NAutomaton Q Σ |
123 → {n : ℕ } → FiniteSet Q {n} | |
69 | 124 → (Nstart : Q → Bool) → List Σ → Bool |
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125 Naccept M fin sb [] = exists fin ( λ q → sb q /\ Nend M q ) |
69 | 126 Naccept M fin sb (i ∷ t ) = Naccept M fin ( Nmoves M fin sb i ) t |
127 | |
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128 Naccept では終了条件を調べる。状態の集合 sb で Nend を満たすものがあることを exists を使って調べればよい。 |
69 | 129 |
37 | 130 |
131 --例題 | |
132 | |
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133 例題1.36 を考えよう。状態遷移関数は以下のようになる。 |
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134 |
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135 transition136 : StatesQ → A2 → StatesQ → Bool |
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136 transition136 q1 b0 q2 = true |
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137 transition136 q1 a0 q1 = true -- q1 → ep → q3 |
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138 transition136 q2 a0 q2 = true |
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139 transition136 q2 a0 q3 = true |
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140 transition136 q2 b0 q3 = true |
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141 transition136 q3 a0 q1 = true |
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142 transition136 _ _ _ = false |
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143 |
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144 教科書にはε遷移(入力がなくても遷移できる)があるが、ここでは、ε遷移先の矢印を全部手元に持ってきてしまうという |
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145 ことしてしまう。 |
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146 |
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147 end136 : StatesQ → Bool |
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148 end136 q1 = true |
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149 end136 _ = false |
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150 |
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151 start136 : StatesQ → Bool |
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152 start136 q1 = true |
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153 start136 _ = false |
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154 |
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155 nfa136 : NAutomaton StatesQ A2 |
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156 nfa136 = record { Nδ = transition136; Nend = end136 } |
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157 |
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158 <a href=" ../agda/nfa136.agda"> 1.36 の例題 </a> |
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159 |
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160 example136-1 = Naccept nfa136 finStateQ start136( a0 ∷ b0 ∷ a0 ∷ [] ) |
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161 |
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162 最初の状態 q1 から a0 ∷ b0 ∷ a0 ∷ [] の入力を受けとる場合を考える。 |
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164 a0 を受けとると、q1 にしか行けない。q1 で b0 を受けとると、q2 に移動する。q2 で a0 を受けとると、q3 か、または、 |
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165 q2 に行ける。どちらも終了状態ではないので、不受理となる。ここで、もう一つ a0 が来れば q3 から q1 に行ける。q2 |
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166 から行けないが、どれかの経路が成功すれば良いので受理となる。 |
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167 |
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168 example136-2 = Naccept nfa136 finStateQ start136( a0 ∷ b0 ∷ a0 ∷ a0 ∷ [] ) |
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169 |
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170 |
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171 --問題 |
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172 |
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173 ... 作成中... |
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174 |
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175 |
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176 --非決定性オートマトンと決定性オートマトン |
37 | 177 |
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178 record Automaton ( Q : Set ) ( Σ : Set ) |
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179 : Set where |
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180 field |
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181 δ : Q → Σ → Q |
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182 aend : Q → Bool |
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183 |
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184 の Q に Q → Bool を入れてみる。 |
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185 |
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186 δ : (Q → Bool ) → Σ → Q → Bool |
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187 aend : (Q → Bool ) → Bool |
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188 |
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189 これを、 |
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190 |
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191 record NAutomaton ( Q : Set ) ( Σ : Set ) |
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192 : Set where |
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193 field |
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194 Nδ : Q → Σ → Q → Bool |
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195 Nend : Q → Bool |
37 | 196 |
104
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197 これの Nδ と Nend から作れれば、NFA から DFA を作れることになる。 |
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198 |
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199 NFAの受理を考えると、状態の集合を持ち歩いて受理を判断している。つまり、状態の集合を状態とする Automaton を考えることになる。 |
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200 |
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201 遷移条件は、状態の集合を受けとって、条件を満たす状態の集合を返せば良い。条件は |
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202 |
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203 Nδ : Q → Σ → Q → Bool |
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204 |
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205 だった。つまり、入力の状態集合を選別する関数 f と、 Nδ との /\ を取ってやればよい。q は何かの状態、iは入力、nq は次の状態である。 |
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206 |
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207 f q /\ Nδ NFA q i nq |
69 | 208 |
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209 これが true になるものを exists を使って探し出す。 |
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210 |
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211 δconv : { Q : Set } { Σ : Set } { n : ℕ } → FiniteSet Q {n} → ( nδ : Q → Σ → Q → Bool ) → (f : Q → Bool) → (i : Σ) → (Q → Bool) |
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212 δconv {Q} { Σ} { n} N nδ f i q = exists N ( λ r → f r /\ nδ r i q ) |
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213 |
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214 ここで、( nδ : Q → Σ → Q → Bool ) は NFAの状態遷移関数を受けとる部分である。 |
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215 |
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216 終了条件は |
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217 |
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218 f q /\ Nend NFA q ) |
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219 ' |
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220 で良い。 これが true になるものを exists を使って探し出す。 |
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221 |
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222 Q が FiniteSet Q {n} であれば |
37 | 223 |
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224 subset-construction : { Q : Set } { Σ : Set } { n : ℕ } → FiniteSet Q {n} → |
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225 (NAutomaton Q Σ ) → (astart : Q ) → (Automaton (Q → Bool) Σ ) |
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226 subset-construction {Q} { Σ} {n} fin NFA astart = record { |
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227 δ = λ f i → δconv fin ( Nδ NFA ) f i |
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228 ; aend = λ f → exists fin ( λ q → f q /\ Nend NFA q ) |
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229 } |
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230 |
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231 という形で書くことができる。状態の部分集合を作っていくので、subset construction と呼ばれる。 |
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232 |
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233 λ f i → δconv fin ( Nδ NFA ) f i |
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234 は |
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235 λ f i q → δconv fin ( Nδ NFA ) f i q |
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236 |
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237 であることに注意しよう。これは、Curry 化の省略になっている。省略があるので、δ : (Q → Bool ) → Σ → Q → Bool という形に見える。 |
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238 |
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239 <a href=" ../agda/sbconst2.agda"> subset construction </a> |
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240 |
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241 --subset constructionの状態数 |
37 | 242 |
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243 実際にこれを計算すると、状態数 n のNFAから、最大、2^n の状態を持つDFAが生成される。しかし、この論理式からそれを |
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244 自明に理解することは難しい。しかし、f は Q → Bool なので、例えば、3状態でも、 |
37 | 245 |
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246 q1 q2 q3 |
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247 false false false |
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248 false false true |
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249 false true false |
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250 false true true |
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251 true false false |
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252 true false true |
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253 true true false |
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254 true true true |
69 | 255 |
104
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256 という8個の状態を持つ。exists は、このすべての場合を尽くすように働いている。 |
69 | 257 |
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258 アルゴリズムとしてこのまま実装すると、 exists が必要な分だけ計算するようになっている。これは結構遅い。 |
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259 前もって、可能な状態を Automaton として探し出そうとすると、 指数関数的な爆発になってしまう。 |
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260 |
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261 実際に、指数関数的な状態を作る NFA が存在するので、これを避けることはできない。 |
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262 |