Mercurial > hg > Members > kono > Proof > ZF-in-agda
comparison src/Tychonoff.agda @ 1172:f4bccbe80540
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author | Shinji KONO <kono@ie.u-ryukyu.ac.jp> |
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date | Sun, 22 Jan 2023 22:41:13 +0900 |
parents | a839fccdef47 |
children | 4b2f49a5a1d5 |
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1171:a839fccdef47 | 1172:f4bccbe80540 |
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187 uflq : UFLP TQ FQ UFQ | 187 uflq : UFLP TQ FQ UFQ |
188 uflq = FIP→UFLP TQ (Compact→FIP TQ CQ) FQ UFQ | 188 uflq = FIP→UFLP TQ (Compact→FIP TQ CQ) FQ UFQ |
189 | 189 |
190 Pf : odef (ZFP P Q) (& < * (UFLP.limit uflp) , * (UFLP.limit uflq) >) | 190 Pf : odef (ZFP P Q) (& < * (UFLP.limit uflp) , * (UFLP.limit uflq) >) |
191 Pf = ? | 191 Pf = ? |
192 neip : {v : Ordinal} → {p q : HOD} → Neighbor (ProductTopology TP TQ) (& < p , q >) v → Neighbor TP (& p) ? | |
193 neip = ? | |
194 neiq : {v : Ordinal} → {p q : HOD} → Neighbor (ProductTopology TP TQ) (& < p , q >) v → Neighbor TQ (& q) ? | |
195 neiq = ? | |
196 pq⊆F : {p q : HOD} → Neighbor TP (& p) (UFLP.limit uflp) → Neighbor TP (& q) (UFLP.limit uflq) → ? ⊆ filter F | 192 pq⊆F : {p q : HOD} → Neighbor TP (& p) (UFLP.limit uflp) → Neighbor TP (& q) (UFLP.limit uflq) → ? ⊆ filter F |
197 pq⊆F = ? | 193 pq⊆F = ? |
198 isL : {v : Ordinal} → Neighbor (ProductTopology TP TQ) (& < * (UFLP.limit uflp) , * (UFLP.limit uflq) >) v → * v ⊆ filter F | 194 isL : {v : Ordinal} → Neighbor (ProductTopology TP TQ) (& < * (UFLP.limit uflp) , * (UFLP.limit uflq) >) v → * v ⊆ filter F |
199 isL {v} npq {x} fx = ? | 195 isL {v} npq {x} fx = filter2 F ? ? ? where |
200 | 196 neip : {p : Ordinal } → ( bp : BaseP TP Q p ) → * p ⊆ filter F |
201 | 197 neip = ? |
202 | 198 neiq : {q : Ordinal } → ( bq : BaseQ P TQ q ) → * q ⊆ filter F |
203 | 199 neiq = ? |
204 | 200 bpq : Base (ZFP P Q) (pbase TP TQ) (Neighbor.u npq) (& < * (UFLP.limit uflp) , * (UFLP.limit uflq) >) |
205 | 201 bpq = Neighbor.ou npq (Neighbor.ux npq) |
202 pqb : Subbase (pbase TP TQ) (Base.b bpq ) | |
203 pqb = Base.sb bpq | |
204 base⊆F : {b : Ordinal } → Subbase (pbase TP TQ) b → * b ⊆ filter F | |
205 base⊆F (gi (case1 px)) bx = ? | |
206 base⊆F (gi (case2 qx)) bx = ? | |
207 base⊆F (g∩ b1 b2) bx = filter1 F ? ? ? | |
208 | |
209 | |
210 | |
211 | |
212 | |
213 |