Mercurial > hg > Members > kono > Proof > ZF-in-agda
diff OD.agda @ 290:359402cc6c3d
definition of filter
author | Shinji KONO <kono@ie.u-ryukyu.ac.jp> |
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date | Fri, 12 Jun 2020 19:19:16 +0900 |
parents | d9d3654baee1 |
children | ef93c56ad311 |
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--- a/OD.agda Sun May 10 09:25:18 2020 +0900 +++ b/OD.agda Fri Jun 12 19:19:16 2020 +0900 @@ -53,9 +53,19 @@ eq← ( ⇔→== {x} {y} eq ) {z} m = proj2 eq m -- next assumptions are our axiom --- it defines a subset of OD, which is called HOD, usually defined as +-- In classical Set Theory, HOD is used, as a subset of OD, -- HOD = { x | TC x ⊆ OD } --- where TC x is a transitive clusure of x, i.e. Union of all elemnts of all subset of x +-- where TC x is a transitive clusure of x, i.e. Union of all elemnts of all subset of x. +-- This is not possible because we don't have V yet. +-- We simply assume V=OD here. +-- +-- We also assumes ODs are isomorphic to Ordinals, which is ususally proved by Goedel number tricks. +-- ODs have an ovbious maximum, but Ordinals are not. This means, od→ord is not an on-to mapping. +-- +-- ==→o≡ is necessary to prove axiom of extensionality. +-- +-- In classical Set Theory, sup is defined by Uion. Since we are working on constructive logic, +-- we need explict assumption on sup. record ODAxiom : Set (suc n) where -- OD can be iso to a subset of Ordinal ( by means of Godel Set )